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function test(str, needle) {
// We should be able to fold away the complete indexOf instruction, because
// executing the right-hand side of the && operator is a no-op.
(str.indexOf(needle) > -1) && needle;
}
const needles = [
"a", "b",
];
for (let i = 0; i < 100; ++i) {
test("aaa", needles[i & 1]);
}